18x^2+30x-828=0

Solution for 18x^2+30x-828=0 equation:

18x^2+30x-828=0

a = 18; b = 30; c = -828;
Δ = b2-4ac
Δ = 302-4·18·(-828)
Δ = 60516
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{60516}=246$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(30)-246}{2*18}=\frac{-276}{36}
=-7+2/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(30)+246}{2*18}=\frac{216}{36}
=6
$